Design a data structure that supports all following operations in average O(1) time.
insert(val)
: Inserts an item val to the set if not already present.remove(val)
: Removes an item val from the set if present.getRandom
: Returns a random element from current set of elements. Each element must have the same probability of being returned.
Example:
// Init an empty set.RandomizedSet randomSet = new RandomizedSet();// Inserts 1 to the set. Returns true as 1 was inserted successfully.randomSet.insert(1);// Returns false as 2 does not exist in the set.randomSet.remove(2);// Inserts 2 to the set, returns true. Set now contains [1,2].randomSet.insert(2);// getRandom should return either 1 or 2 randomly.randomSet.getRandom();// Removes 1 from the set, returns true. Set now contains [2].randomSet.remove(1);// 2 was already in the set, so return false.randomSet.insert(2);// Since 2 is the only number in the set, getRandom always return 2.randomSet.getRandom();
1. 对于insert和remove,需要在O(1)的时间内查看该value是否存在,并insert/remove该value,因此考虑hash table。 2. 对于getRandom,考虑用array来实现,因为:1)access每个元素的probablity相同;2)可以在O(1)时间内access任意元素。
1 class RandomizedSet { 2 public: 3 /** Initialize your data structure here. */ 4 RandomizedSet() { 5 6 } 7 8 /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */ 9 bool insert(int val) {10 if(map.find(val)==map.end()){ //val not presented in the set11 map[val]=data.size();12 data.push_back(val);13 return true;14 }15 16 return false;17 }18 19 /** Removes a value from the set. Returns true if the set contained the specified element. */20 bool remove(int val) {21 if(map.find(val)!=map.end()){ // val presented in the set22 int index = map[val];23 map.erase(val);24 25 //swap the index of the removed value with the last element's index26 int lastIndex = data.size()-1;27 if(index!=lastIndex){28 map[data[lastIndex]] = index;29 data[index]=data[lastIndex];30 }31 data.pop_back();32 return true;33 }34 35 return false;36 }37 38 /** Get a random element from the set. */39 int getRandom() {40 return data[rand()%data.size()];41 }42 private:43 vector data; //data[index] = val44 unordered_mapmap; //map[val] = index45 };46 47 /**48 * Your RandomizedSet object will be instantiated and called as such:49 * RandomizedSet obj = new RandomizedSet();50 * bool param_1 = obj.insert(val);51 * bool param_2 = obj.remove(val);52 * int param_3 = obj.getRandom();53 */
Remove分兩步:
1. 把val从hash table里除去,hash table里的key是val,value是array里相应的index。
2.把val从array里除去,其中要除去的index是从hash table里查出的。具体做法是:将array[index]和array的最后的index互换,然后将array的size减一。因为array[index]和array[size-1]互换,hash table里的array[index] val也需要更新。
注意:当index是size-1时,不需要做:array[index]和array[size-1]互换,hash table里的array[index] val更新
方法二:
先将hash table更新,然后把hash table和array里的元素remove掉
1 class RandomizedSet { 2 public: 3 /** Initialize your data structure here. */ 4 RandomizedSet() { 5 6 } 7 8 /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */ 9 bool insert(int val) {10 if(map.find(val)!=map.end()){ //val already exists11 return false;12 }13 array.push_back(val);14 map[val]=array.size()-1;15 return true;16 }17 18 /** Removes a value from the set. Returns true if the set contained the specified element. */19 bool remove(int val) {20 if(map.find(val)==map.end()){ //val not exist21 return false;22 }23 24 int index=map[val];25 map[array[array.size()-1]]=index;26 array[index]=array[array.size()-1];27 array.pop_back();28 map.erase(val);29 30 return true;31 }32 33 /** Get a random element from the set. */34 int getRandom() {35 if(array.size()>0){36 int index=rand()%array.size();37 38 return array[index];39 }40 return 0;41 }42 private:43 unordered_mapmap;44 vector array;45 };46 47 /**48 * Your RandomizedSet object will be instantiated and called as such:49 * RandomizedSet obj = new RandomizedSet();50 * bool param_1 = obj.insert(val);51 * bool param_2 = obj.remove(val);52 * int param_3 = obj.getRandom();53 */